Let 1st integer = x,
 2nd integer = x+1
 
 As per given condition
 1/3x + 1/4(x+1) = 23
 
 Solve parenthesis and we get;
 1/3x + 1/4x + 1/4 = 23
 (4x + 3x + 3)/12 = 23
 
 multiply both sides by 12 and we get;
 4x + 3x + 3 = 276
 
 Add like terms and we get;
 7x + 3 = 276
 
 subtract 3 from both sides and we get;
 7x = 273
 
 Divide both side by 7 and we get;
 x = 39
 
 So, Let 1st integer = x = 39,
 2nd integer = x+1 = 39 + 1 = 40 |