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Home >> Equality >> Multiply with different numbers >>

## Multiply both sides of equality with different numbers

 Add same number Add different number Subtract same number Subtract different number Multiply with same number Multiply with different numbers Divide by same number Divide by different number

 Explanation: When the sides of equation i.e. L.H.S. and R.H.S of the equation are multiplied with different numbers, the equality fails to holds. Let's understand it with the help of following examples: Example 1 - Multiply L.H.S. by 2 and R.H.S. by 3 of given equation and check what happens to equality 2 X 10 = 5 X 4 Solution - This proceeds as : Multiply L.H.S. by 2 and R.H.S. by 3 of given equation and we get; 2 X 10 X 2 = 5 X 4 X 3 Solve L.H.S. and we get; L.H.S. = 2 X 10 X 2 L.H.S. = 40 Solve R.H.S. and we get R.H.S. = 5 X 4 X 3 R.H.S. = 60 Since L.H.S. in not equals to R.H.S i.e. 40 is not equal to 60 So the given equation 2 X 10 = 5 X 4 fails to hold equality, when we multiply L.H.S. by 2 and R.H.S. by 3 of given equation and hence we get that "When the sides of equation i.e. L.H.S. and R.H.S of the equation are multiplied with different numbers, the equality fails to holds." Example 2 - Multiply L.H.S. by 5 and R.H.S. by 7 of given equation and check what happens to equality 5 + 2 = 6 + 1 Solution - This proceeds as: Multiply L.H.S. by 5 and R.H.S. by 7 of given equation and we get; (5 + 2) X 5 = (6 + 1) X 7 Solve L.H.S. and we get; L.H.S. = (5 + 2) X 5 L.H.S. = 35 Solve R.H.S. and we get R.H.S. = (6 + 1) X 7 R.H.S. = 49 Since L.H.S. in not equals to R.H.S i.e. 35 is not equal to 49 So the given equation 5 + 2 = 6 + 1 fails to hold equality, when we multiply L.H.S. by 5 and R.H.S. by 7 of given equation and hence we get that "When the sides of equation i.e. L.H.S. and R.H.S of the equation are multiplied with different numbers, the equality fails to holds."

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