Factorize 14y2 + 19y - 3 by splitting the middle term |
14y2 + 19y - 3
Now, we have to find 2 numbers whose
sum is 19 (middle term) and when
multiplied (first and last term) i.e. 14 X (-3) = -42
So these two numbers are -
21 - 2 = 19
21 X (-2) = -42
Now we put both 21 and (-2) numbers in the middle term of 19y and we get
∴ 14y2 + 19y - 3 = 14y2 + 21y - 2y - 3
or 7y(2y + 3) -1(2y - 3)
or (7y - 1) (2y + 3)
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