In the following diagram:
CO is a bisector of ∠ AOB
∠ 1 = ∠ 2
Prove △ OBC ≅ △ OAC |
In the given triangle:
∠ BCO = ∠ ACO (CO is a bisector of ∠ AOB)
∠ 1 = ∠ 2 (given)
CO = CO (common side)
Therefore, ASA rule of congruence applies here and we get following corresponding relationships:
A ↔ B
O ↔ O
C ↔ C
Hence, △ OBC ≅ △ OAC
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Related Question Examples
In the following diagram:
CO is a bisector of ∠ AOB
∠ 1 = ∠ 2
Prove △ OBC ≅ △ OAC |
In the following diagram:
∠ QPS = ∠ PQR
∠ PQS = ∠ QPR
Prove △ SPQ ≅ △ RQP |
In the following diagram:
DO = CO
∠ 1 = ∠ 2
Prove △ AOD ≅ △ BOC |
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