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Home >> Polynomials >> Quadratic Equation >> Discriminant of Quadratic equation >>

Discriminant of Quadratic equation

Standard Form of Quadratic Equation Finding roots of Quadratic Equation Discriminant of Quadratic equation

Discriminant of a quadratic equation, ax2 + bx + c = 0, can be found by finding the values using b2 – 4ac.

Now, on solving b2 – 4ac, you will get following three types of solutions of a quadratic equation:

1) b2 – 4ac > 0
2) b2 – 4ac < 0
3) b2 – 4ac = 0

In 1st condition, b2 – 4ac > 0, the given quadratic equation has two distinct real roots.

In 2nd condition, b2 – 4ac < 0, the given quadratic equation has no real roots.

In 3rd condition, b2 – 4ac = 0, the given quadratic equation has two equal real roots.

Now, let’s understand all the three conditions with the help of following examples.

1st Condition : b2 – 4ac > 0, the given quadratic equation has two distinct real roots.Consider the following quadratic equation:

2x2 -5x + 3 = 0


You can use any method to find the roots of the given quadratic equation. In this website, we have explained two methods of finding roots of quadratic equations:

1) Factorization method - Splitting middle term

2) Quadratic Equation: x = -b + ( b 2 - 4ac )
2a


Now, on applying any of the above method, we get roots of given quadratic equation, 2x2 -5x + 3 = 0, as shown below:

x = 3/2 and x = 1 are the roots of given quadratic equation.

So, you can see that the roots of x are distinct as well as real numbers.

Hence, this satisfy 1st condition which say that if b2 – 4ac > 0, then the given quadratic equation has two distinct real roots.




2nd Condition : To understand condition 2, b2 – 4ac < 0, the given quadratic equation has no real roots.Consider the following quadratic equation:

5x2 -6x - 2 = 0


Use quadratic equation to find the roots of the given quadratic equation and roots are as follows:

x = 3 + ( 19 )
5
and x = 3 - ( 19 )
5


So, you can see that the roots of x are unreal numbers.

Hence, this satisfy 2nd condition which says that if b2 – 4ac < 0, then the given quadratic equation has no real root




3rd Condition : To understand condition 3, b2 – 4ac = 0, the given quadratic equation has two equal real roots. Consider the following quadratic equation:

x2 +2x +1 = 0


Here also, you can use any method to find the roots of the given quadratic equation. In this website, we have explained two methods of finding roots of quadratic equations:

1) Factorization method - Splitting middle term

2) Quadratic Equation: x = -b + ( b 2 - 4ac )
2a


Now, on applying any of the above method, we get roots of given quadratic equation, 2x2 -5x + 3 = 0, as shown below:

x = -1 and x = -1 are the roots of given quadratic equation.

So, you can see that the roots of x are equal numbers.

Hence, this satisfy 3rd condition which says that if b2 – 4ac = 0, then the given quadratic equation has two equal real roots.

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