Arithmetic
Arithmetic Progression
Associative Property
Averages
Brackets
Closure Property
Commutative Property
Conversion of Measurement Units
Cube Root
Decimal
Divisibility Principles
Equality
Exponents
Factors
Fractions
Fundamental Operations
H.C.F / G.C.D
Integers
L.C.M
Multiples
Multiplicative Identity
Multiplicative Inverse
Numbers
Percentages
Profit and Loss
Ratio and Proportion
Simple Interest
Square Root
Unitary Method
Algebra
Cartesian System
Order Relation
Polynomials
Probability
Standard Identities & their applications
Transpose
Geometry
Basic Geometrical Terms
Circle
Curves
Angles
Define Line, Line Segment and Rays
Non-Collinear Points
Parallelogram
Rectangle
Rhombus
Square
Three dimensional object
Trapezium
Triangle
Trigonometry
Trigonometry Ratios
Data-Handling
Arithmetic Mean
Frequency Distribution Table
Graphs
Median
Mode
Range

Videos
Solved Problems
Home >> Equality >> Add different number >>

## Add different number to the sides of equality

 Add same number Add different number Subtract same number Subtract different number Multiply with same number Multiply with different numbers Divide by same number Divide by different number

 Explanation:When different numbers are added to the sides of equation i.e. L.H.S. and R.H.S of the equation, the equality fails to hold. Let's understand it with the help of following examples: Example 1 - Add 5 to L.H.S. and 4 to R.H.S. of given equation and check what happens to equality 2 + 4 = 9 - 3 Solution - This proceeds as : Add 5 to L.H.S. & 4 to R.H.S. of given equation and we get; 2 + 4 + 5 = 9 - 3 + 4 Solve L.H.S. and we get; L.H.S. = 2 + 4 + 5 L.H.S. = 11 Solve R.H.S. and we get R.H.S. = 9 - 3 + 4 Now solve as per BODMAS rule and we get; R.H.S. = 10 Since L.H.S. in not equals to R.H.S i.e. 11 is not equal to 10 So the given equation 2 + 4 = 9 - 3 fails to hold equality, when we add 5 to L.H.S. and 4 to R.H.S. of given equation and hence we get that "When different numbers are added to the sides of equation i.e. L.H.S. and R.H.S of the equation, the equality fails to hold." Example 2 - Add 10 to L.H.S. and 5 R.H.S. of given equation and check what happens to equality 10 - 3 = 20 - 13 Solution - This proceeds as : Add 10 to L.H.S. & 5 to R.H.S. of given equation and we get; 10 + 10 - 3 = 5 + 20 - 13 Solve L.H.S. and we get; L.H.S. = 10 + 10 - 3 Now solve as per BODMAS rule and we get; L.H.S. = 27 Solve R.H.S. and we get R.H.S. = 5 + 20 - 13 Now solve as per BODMAS rule and we get; R.H.S. = 12 Since L.H.S. in not equals to R.H.S i.e. 27 is not equal to 12 So the given equation 10 - 3 = 20 - 13 fails to hold equality, when we add 10 to L.H.S. and 5 to R.H.S. of given equation and hence we get that "When different numbers are added to the sides of equation i.e. L.H.S. and R.H.S of the equation, the equality fails to hold."

Copyright@2022 Algebraden.com (Math, Algebra & Geometry tutorials for school and home education)