If Sec Θ = 11/13, find Cosec Θ and Cot Θ |
Lets draw the right angle triangle with the above mentioned details
Given thing are
Sec Θ = 11/13
we know that Sec Θ = Hypotenuse / Adjacent Side, so we get
Adjacent Side = 11
Hypotenuse = 13
Hypotenuse : BC = 13
Adjacent Side : AB = 13 (Adjacent to ∠ Θ)
Opposite Side : AC = ? (Opposite to ∠ Θ)
To find the Opposite Side - AC , we use Pythagoras theorem ((Hypotenuse)2 = (Leg 1)2 + (Leg 2)2)
| ____________ | AC = √ | BC2 - AB2 |
| ____________ | AC = √ | 132 - 112 |
| ____________ | AC = √ | 169 - 121 |
Now, we will simplify square root
| _________________ | AC = √ | 2 x 2 x 2 x 2 x 3 |
| __ | AC = 2 + 2 √ | 3 (pairs taken out) |
So Cosec, Sec and Cot will be as follows -
Cosec Θ = Hypotenuse / Opposite Side
Cot Θ = Adjacent Side / Opposite Side
Sec Θ = Hypotenuse / Adjacent Side
Sec Θ = 13/11
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