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Home >> Rhombus >> Construction of Rhombus with Compass >>

## Construction of Rhombus with Compass

 Area of Rhombus Difference & Similarity between Rhombus & Rectangle Difference & Similarity between Rhombus & Square Difference & Similarity between Rhombus & Parallelogram Construction of Rhombus with Compass

What is Rhombus and Diagonals of Rhombus ?
How to construct Perpendicular Bisector of Line Segment ?

Construction of Rhombus

Here you will understand how to construct a Rhombus; where only measure of its two diagonals are given.

Example: Construct Rhombus PQRS, where two diagonals PR and SQ are 5 cm and 7 cm respectively.
Solution: As per the given question
PR & SQ are diagonals of Rhombus PQRS
PR = 5 cm
SQ = 7 cm

Steps of construction are as follows:
Step 1: Use ruler and draw line segment SQ of 7 cm, which is also one of the diagonal (as shown below):

Step 2: Use compass and draw perpendicular bisector of line segment SQ (as shown below):
Note: We construct perpendicular bisector because in Rhombus, diagonals are perpendicular bisector to each other.

Step 3: Mark point of intersection (line segment and perpendicular bisector) as O (as shown below):

Step 4: Use compass and 2.5 cm wide open. With O as center, draw two arcs, cutting perpendicular bisector at point P and R (as shown below):
Note: Here we have chosen length of 2.5 cm because in Rhombus diagonals bisect each other at point of intersection. Since length of other diagonal is 5 cm (as given), so half of 5 cm is 2.5 cm

Step 5: Use ruler and join points P & S, P & Q, S & R and R & Q. And we get the resultant Rhombus PQRS (as shown below)