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Home >> Trigonometry Ratios >> Find Height, Distance using T - Ratios >> Angle of Elevation >>

Angle of Elevation and find Height & Distance

Angle of Elevation Angle of Depression

Before you study this topic you should know what is angle of elevation and depression:

What is Angle of Elevation ?

The formulas we used in angle of elevation :

To find height and distance we use Tan θ = Opposite Side / Adjacent Side
To find length or hypotenuse we use Sin θ = Opposite Side / Hypotenuse





Example 1 : A person is standing 5m away from tree, the angle of elevation of the top of tree is 60 find the height of tree ?
Solution : Let AB is the tree. B is the foot and A is the top of tree. C is the point on the ground where the person is standing and which is making the angle of elevation of 60°

If we draw a picture it will look like as below -



so we get
CB (Distance from tree) = 5m
∠BCA = 60°
Right angle is at point B
AB (Height) = ?

A right angle triangle △ ABC is formed in which
AB is the Opposite Side from angle of elevation
BC is the Adjacent Side from angle of elevation

We know that Tan θ = Opposite Side / Adjacent Side

tan 60° = AB
BC


 3  = AB
10


AB = 10 x  3 


Value of  3  is 1.73 so,

AB = 5 x 1.73 = 8.65

AB = 8.65m is the height of tree




Example 2 :Height of tree is 8.65m, the angle of elevation of the top of tree is 60 find the distance at which the person is standing away from tree ?
Solution : Let AB is the tree. B is the foot and A is the top of tree. C is the point on the ground where the person is standing and which is making the angle of elevation of 60°

If we draw a picture it will look like as below -



so we get
CB (Distance from tree) = ?
∠BCA = 60°
Right angle is at point B
AB (Height) = 8.65m

A right angle triangle △ ABC is formed in which
AB is the Opposite Side from angle of elevation
BC is the Adjacent Side from angle of elevation

We know that Tan θ = Opposite Side / Adjacent Side

tan 60° = AB
BC


 3  = AB
10


AB = 10 x  3 


Value of  3  is 1.73 so,

8.65 = CB x 1.73
CB = 8.65 / 1.73
CB = 5

so the person is standing 5m away from the tree




Example 3 : A tree is 5m high. If angle of elevation is 45° find the hypotenuse

Let AB is the tree. B is the foot and A is the top of tree. C is the point on the ground where a person is standing and which the angle of elevation of 45°

If we draw a picture it will look like as below -



so we get
AC = ?
∠ BCA = 45°
AB = 5m

A right angle triangle △ ABC is formed in which
AB is the Opposite Side from angle of elevation
AC is the Hypotenuse Side

We know that Sin θ = Opposite Side / Hypotenuse

sin 45° = AB
AC


   1   
 2 
= 5
AC


AC = 5 x  2 

Value of  2  is 1.41 so,

5 x 1.41 = 7.05

AC = 7.05m is the hypotenuse

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Study More Solved Questions / Examples

  • At a point 20m away from the foot of a building, the angle of elevation of the top of building is 30° find the height of building
  • At a point 10m away from the foot of a building, the angle of elevation of the top of building is 30° find the height of building
  • At a point 10m away from the foot of a building, the angle of elevation of the top of building is 60° find the height of building
  • A tower is 10m high. A steel wire is tied at the top of pole and is affixed at a point on the ground. If the steel wire makes an angle of 45° find the length of steel wire
  • A mountain is 90m high. A steel wire is tied at the top of mountain and is affixed at a point on the ground. If the steel wire makes an angle of 45° find the length of steel wire
  • A mountain is 50m high. A steel wire is tied at the top of mountain and is affixed at a point on the ground. If the steel wire makes an angle of 30° find the length of steel wire
  • A pole is 30m high. A steel wire is tied at the top of pole and is affixed at a point on the ground. If the steel wire makes an angle of 30° find the length of steel wire
  • A building is 70m high. A steel wire is tied at the top of pole and is affixed at a point on the ground. If the steel wire makes an angle of 30° find the length of steel wire
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